Nuclear Medicine Exit Practice Exam 2025 - Free Nuclear Medicine Practice Questions and Study Guide

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How much decay occurs for Ga-67 over a period of 27 hours?

Approximately 0.5 mCi

Approximately 0.787

Gallium-67 has a half-life of approximately 78 hours. To determine how much decay occurs over a 27-hour period, you can use the concept of half-lives and the decay formula.

The decay formula can be expressed mathematically as:

\[ N(t) = N_0 \times \left( \frac{1}{2} \right)^{t/T_{\frac{1}{2}}} \]

Where:

- \( N(t) \) is the remaining quantity after time \( t \)

- \( N_0 \) is the initial quantity

- \( t \) is the time elapsed

- \( T_{\frac{1}{2}} \) is the half-life

In this scenario, after 27 hours, one would calculate how many half-lives fit into that time frame. Since 27 hours is less than one-half of the 78-hour half-life, there will be some decay, but only a fraction of a half-life has passed. The decay factor can be computed by determining:

\[ \text{Decay Factor} = \left( \frac{1}{2} \right)^{27/78} \]

Using this calculation, you can deduce the remaining

Get further explanation with Examzify DeepDiveBeta

Approximately 0.9

Approximately 1.2

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